A 500 Ml Container Is Filled With Helium Gas To A Pressure Of 3.0 Atm At 250\Xb0c.Approximately How Many Toy Balloons At Stp Can Be Filled By Helium F

A 500 mL container is filled with helium gas to a pressure of 3.0 atm at 250°C.approximately how many toy balloons at STP can be filled by helium from this container,assuming each balloon can contain 1L? recall that STP means standard temperature and pressure (1 atm and 273 k).

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Problem:

A 500 mL container is filled with helium gas to a pressure of 3.0 atm at 25.0°C.approximately how many toy balloons at STP can be filled by helium from this container,assuming each balloon can contain 1L? recall that STP means standard temperature and pressure (1 atm and 273 k).

First we have to solve for the amount of gas:

1000 ml = 1L  (500 ml × 1L / 1000 ml = .5 L)

K = 25.0 + 273.15 = 298.15 K

Given Data:

V (volume) = 500 mL or .5 L

P (pressure) = 3.0 atm

T (temperature) = 25.0°C or 298.15 K

n (moles) = ? unknown

R (universal constant) = 0.0821 L.atm/mol.K

Solution:

We can use the formula PV = nRT, to solve for n, we use n = PV/RT

n = PV/RT

  = 3.0 atm × .5 L / 0.0821 L.atm/mol.K × 298.15 K

  = 1.5 / 24.478 /mol

  = 0.0612 mol

Convert 0.0612 mol of He to volume at stp

1 mole = 22.4 L at stp

0.0612 mol × 22.4 L / 1 mol = 1.37 Liters

Answer:

The helium gas contains 0.0612 mole which is equivalent to 1.37 L at stp.

It can only filled 1 toy balloon at STP and another balloon for only .37 L.