The Number Of Moles Present In 38.00 G Of Nh3 Is

The number of moles present in 38.00 g of NH3 is

 

NH3.

Determine the molar mass first

Note that the molecule has a total of one nitrogen atom and threehydrogen atoms.

You multiply the atomic mass of nitrogen by 1 and hydrogen by 3 and then add the results to get the total molar mass in grams per mole.

The atomic masses of nitrogen and hydrogen are 14. 01 and 1.008, respectively.

Multiplying the masses and quantities gives you (14.01 x 1) + (1.008 x 3) = 14.01+ 3. 024 = 17.034 grams per moles.

Calculate the moles of the solution by dividing the mass in grams by the grams per mole

38.00g÷17.034 g/mol

=2.2308 mol

The number of moles present is 2.2308 mol